I haven't figured out how to move from 4 to 5 yet, so if you have any suggestions please let me know.

## 28 July 2009

## 13 July 2009

### With a nod to the set theorists

All numbers arise from 0, from which spills forth equally number and numeration.

From 0 comes 1, unity, which comes from the placement of 0 within a context.

1 = 1 = 2, or, to put it better, {0, {0}} = 2. Though since 1 x 2 = 2, it may seem that 2 is higher than 1, the existence of 2 depends entirely upon 1 and without 1 it would be nothing at all.

2 comes into being immediately upon the definition of 1. This same movement makes possible the emergence of 3. The motion towards 1 (present in all numbers) in 2 impels the separation of 2 into both itself and that of itself that turns back towards one. Thus,

2 = (1 = 1)

2 = {0, {0}}

However, these two formulations are not strictly the same, for the first stresses the unity towards 1 in 2 while the second stresses the manner in which 2 is spun forth from 1. The dissimilarity-within-itself of 2 gives rise to three, since

2 = (1 = 1) = 1

1 + {0, {0}} = 1 + 2 = 3

From 0 comes 1, unity, which comes from the placement of 0 within a context.

1 = 1 = 2, or, to put it better, {0, {0}} = 2. Though since 1 x 2 = 2, it may seem that 2 is higher than 1, the existence of 2 depends entirely upon 1 and without 1 it would be nothing at all.

2 comes into being immediately upon the definition of 1. This same movement makes possible the emergence of 3. The motion towards 1 (present in all numbers) in 2 impels the separation of 2 into both itself and that of itself that turns back towards one. Thus,

2 = (1 = 1)

2 = {0, {0}}

However, these two formulations are not strictly the same, for the first stresses the unity towards 1 in 2 while the second stresses the manner in which 2 is spun forth from 1. The dissimilarity-within-itself of 2 gives rise to three, since

2 = (1 = 1) = 1

1 + {0, {0}} = 1 + 2 = 3

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